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π₯ #MASALA_YECHIMI π₯
βοΈ DNK molekulasi ma'lum bir fragmentining uzunligi 107,1 nm (nukleotidlar orasidagi masofa 0,34 nm). DNK ning ushbu fragmentida 780 ta vodarod bog'i mavjud bo'lsa, undagi Guanin nukleotidlari sonini aniqlang
A) 150 ta
B) 165 ta
C) 240 ta
D) 180 ta
γ½οΈγ½οΈ #YECHIMI γ½οΈγ½οΈ
1β£ β Usul tenglama:
1) 107,1:0,34 = 315
2) 315 β’ 2 = 630
3) 2x + 2y = 630
2x + 3y = 780
x = 165
y = 150
2β£ β Usul dioganal:
1) 107,4:0,34=315
2) 315 β’ 2 = 630
3) 315 β’ 3 = 945
630 165 A va T
\ /
780
/ \
945 150 G va S
3β£ β Usul qoida:
Umumiy H bogΚ»idan umumiy nukleotidlar ayirmasi G yoki S nukleotidini beradi.
780 - 630 = 150 G yoki S soni
Javob: A) 150 ta β
Tushunmaganlar bemalol murojaat qilishi mumkin.π
π¨π»βπ» OYBEK_Alisherovich
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βοΈβοΈ #TARQATING βοΈβοΈ
γ½οΈ @Super_Biologiya_Uz
γ½οΈ @Super_Biologiya_Uz
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