PHYS_Q Telegram 6722
💢 هولوگرافیک یونیورس ⁴


Take y² = x⁵ - x and try to solve for y:
y = sqrt(x⁵ - x)
This is double-valued so we get a branched double cover of the sphere, with branch points where x⁵ - x is zero or infinity.
And where are those points?
They're the vertices of an octahedron!‌‌

معادله :
y² = x⁵ - x
را در نظر بگیرید و تلاش کنید نسبت به y آنرا حل کنید:

y = sqrt(x⁵ - x)
این دو مقدار مثبت و منفی را بدست می دهد. بنابراین ما یک ارزش دابل منشعب از کره به دست می آوریم، با نقاط انشعاب که در آن x⁵ - x صفر یا بی نهایت است.
و آن نقاط کجاست؟
آنها رئوس یک هشت وجهی هستند!‌‌

💢@higgs_field



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💢 هولوگرافیک یونیورس ⁴


Take y² = x⁵ - x and try to solve for y:
y = sqrt(x⁵ - x)
This is double-valued so we get a branched double cover of the sphere, with branch points where x⁵ - x is zero or infinity.
And where are those points?
They're the vertices of an octahedron!‌‌

معادله :
y² = x⁵ - x
را در نظر بگیرید و تلاش کنید نسبت به y آنرا حل کنید:

y = sqrt(x⁵ - x)
این دو مقدار مثبت و منفی را بدست می دهد. بنابراین ما یک ارزش دابل منشعب از کره به دست می آوریم، با نقاط انشعاب که در آن x⁵ - x صفر یا بی نهایت است.
و آن نقاط کجاست؟
آنها رئوس یک هشت وجهی هستند!‌‌

💢@higgs_field

BY کوانتوم مکانیک‌




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